sprinkles671 sprinkles671
  • 03-09-2018
  • Mathematics
contestada

The opposite of one third of a number, x, decreased by 2 is greater than 2 and less than 8. What are the possible solutions?

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GoddessofDork
GoddessofDork GoddessofDork
  • 03-09-2018

So this is our inequality: [tex] 2<-\frac{1}{3}x-2<8 [/tex]

Firstly, add 2 to all sides of the inequality: [tex] 4<-\frac{1}{3}x<10 [/tex]

Next, multiply all sides of the inequality by -3, and since we are multiplying by a negative number flip the signs, and your answer will be: [tex] -12>x>-30 [/tex]

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