Answer:
x1=0.333, x2=-7
Step-by-step explanation:
[tex]6 {x}^{2} + 40x - 14 = 0 \\ \\ divide \: through \: by \: 2 \\ 3 {x}^{2} + 20 x - 7 = 0 \\ write \: 20x \: as \: a \: difference \\ 3x + 21x - x - 7 = 0 \\ (3 {x}^{2} + 21x) - (x + 7) = 0\\ 3x(x + 7) - (x + 7) = 0 \\ (3x - 1)(x + 7) = 0 \\ 3x - 1 = 0 \\ 3x = 1 \\ x = \frac{1}{3} \\ \\ x + 7 = 0 \\ x = - 7[/tex]
