nicholsj180 nicholsj180
  • 04-12-2020
  • Mathematics
contestada

need help once again!

need help once again class=

Respuesta :

7492
7492 7492
  • 04-12-2020

Answer:

θ = cos-1 (38/47)

Step-by-step explanation:

sin θ = [tex]\frac{opposite}{hypotenuse} = \frac{27}{47}\\[/tex]

θ = sin-1 (27/47)

cos θ = [tex]\frac{adjacent}{hypotenuse} = \frac{38}{47}[/tex]

θ = cos-1 (38/47)

tan θ = [tex]\frac{opposite}{adjacent} = \frac{27}{38}[/tex]

θ = tan-1 (27/38)

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