Answer:
[tex]46620\ \text{N}[/tex]
Explanation:
m = Mass of roller coaster = 2000 kg
r = Radius of loop = 24 m
v = Velocity of roller coaster = 18 m/s
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Normal force at the point will be
[tex]N-mg=\dfrac{mv^2}{r}\\\Rightarrow N=\dfrac{mv^2}{r}+mg\\\Rightarrow N=\dfrac{2000\times 18^2}{24}+2000\times 9.81\\\Rightarrow N=46620\ \text{N}[/tex]
The force exerted on the track is [tex]46620\ \text{N}[/tex].
