kassxndrax kassxndrax
  • 03-01-2022
  • Mathematics
contestada

I need help in this ixl

I need help in this ixl class=

Respuesta :

itsandypandy
itsandypandy itsandypandy
  • 03-01-2022

Answer:

[tex]t^{9}s^{8}[/tex]

Step-by-step explanation:

[tex]s^{0} = 1; u^{-1} = \frac{1}{u} \\1(t)(\frac{1}{u})(s^{8})(t^{8})(u)\\\frac{(t^{1+8})(s^{8})(u)}{u}\\t^{9}s^{8}[/tex]

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