Respuesta :

we have the equation

[tex]x^2+3x+12=0[/tex]

Solve using the formula

a=1

b=3

c=12

substitute

[tex]x=\frac{-3(+-)\sqrt{3^2-4(1)(12)}}{2(1)}[/tex][tex]x=\frac{-3(+-)\sqrt{-39}}{2}[/tex]

Remember that

i^2=-1

so

[tex]x=\frac{-3(+-)i\sqrt{39}}{2}[/tex]

The answer is the fourth option

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