JaeliY203331 JaeliY203331
  • 03-11-2022
  • Physics
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Hi I just answered a question for electricity grade 12 could you please if it is correct

Hi I just answered a question for electricity grade 12 could you please if it is correct class=

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MiagraceI342934 MiagraceI342934
  • 03-11-2022

F = k*(q1)*(q2)/r^2

We know that:

F = 71 N

k = coulomb's constant = 9*10^9

q1 = ?

q2 = ?

We know that q1 = q2, since in the question it states that the charges are identical.

r = 0.99 m

F = k*(q1)*(q1)/r^2

F = k*(q1)^2/r^2

71 = 9*10^9 * (q1)^2 / 0.99^2

Isolating (q1)^2,

71 * 0.99^2 / (9*10^9) = (q1)^2

Taking square root of both sides to get q1 to the power of 1,

sqrt( 71 * 0.99^2 / (9*10^9) ) = q1

Now, simplifying the left side in a calculator, we get that

q1 = 8.793 * 10^-5 C = q2

Answer Link

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