Stas747
Stas747
04-05-2015
Mathematics
contestada
How do I solve this.
Log 5x = log (2x+9)
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konrad509
konrad509
04-05-2015
[tex]D:5x\ \textgreater \ 0 \wedge 2x+9\ \textgreater \ 0\\ D:x\ \textgreater \ 0 \wedge 2x\ \textgreater \ -9\\ D:x\ \textgreater \ 0 \wedge x\ \textgreater \ -\dfrac{9}{2}\\ D:x\ \textgreater \ 0\\\\ \log5x=\log(2x+9)\\ 5x=2x+9\\ 3x=9\\ x=3[/tex]
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