Answer:
n/(n+1) . . . . n ≠ 1
Step-by-step explanation:
As written, there is no product. There is ony the sum ...
[tex]4\dfrac{n}{4}-4n-\dfrac{1}{n}+1[/tex]
With appropriate parentheses, this becomes the product of rational functions ...
... (4n)/(4n-4)·(n-1)/(n+1)
[tex]=\dfrac{4n(n-1)}{4(n-1)(n+1)}=\dfrac{n}{n+1}[/tex]
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At n=1, the product has a "hole" where the denominator of the original expression is zero, so the expression is undefined. Hence the domain of the product must be restricted to n≠1 (as well as n≠-1).
